What is the charge on a circular disc with a varying charge density?

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SUMMARY

The discussion focuses on calculating the total charge on a circular disc with a varying charge density defined by ρs = ρs0 (e^−ρ) sin²(φ) C/m². The integration limits for the radial coordinate ρ are confirmed as 0 to a, and for the angular coordinate φ as 0 to 2π. The integral for total charge Q is expressed as Q = ∫∫ρs0 (e^−ρ) sin²(φ) dφ dρ. The integration can be effectively performed using computational tools like Wolfram Alpha, which simplifies the process of evaluating the integral.

PREREQUISITES
  • Understanding of charge density concepts in electrostatics
  • Familiarity with double integrals in polar coordinates
  • Knowledge of exponential functions and trigonometric identities
  • Experience using computational tools for integral evaluation, such as Wolfram Alpha
NEXT STEPS
  • Study the application of double integrals in electrostatics
  • Learn about varying charge densities and their implications
  • Explore the use of Wolfram Alpha for solving complex integrals
  • Investigate the properties of sin²(φ) in integration
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Students in physics or engineering, particularly those studying electromagnetism and integral calculus, will benefit from this discussion.

technicolour1
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Homework Statement


Find the total charge on a circular disc of radius ρ = a if the charge density is given by
ρs = ρs0 (e^−ρ) sin2 φ C/m2 where ρs0 is a constant.
Are the two limits of integration from 0 -> a for ρ and 0->2∏ for φ? In the example given in the notes, ρ varies, instead of being a constant value. Does this mean that I cannot integrate ρ in this problem?

Homework Equations



Q = ∫ρdS

The Attempt at a Solution



Q = ∫∫ρs0 (e^−ρ) sin^2 (φ) dφdρ...
 
Last edited:
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With the sin term it looks like there is as much positive as negative?

Edit, now I see the sin^2

Your integral looks doable.
 

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