What is the Charge on the Farther Half of the Rod?

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SUMMARY

The discussion centers on the electrostatic behavior of a neutral metal rod when exposed to a charged sphere with a charge of 1×10^8 units of negative charge. When the sphere is brought near the rod, the half of the rod closer to the sphere acquires a surplus charge of 2×10^4 units. By applying the principle of conservation of charge, it is determined that the half of the rod farther from the sphere must carry a charge of -2×10^4 units, ensuring the total charge of the rod remains zero.

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OP warned about not using the homework template
I'm totally confused what the question is asking. I do not know how to start... please help

A charged sphere with 1×108 units of negative charge is brought near a neutral metal rod. The half of the rod closer to the sphere has a surplus charge of 2×10^4 units. What is the magnitude of the charge on the half of the rod farther from the sphere?
 
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The rod was initially neutral, so the total charge it carries is zero. After a charged sphere is brought near to one end of the rod, the charges in the rod redistribute themself such that the half closer to the rod now is more positively charged with the said amount. Using the argument of conservation of total charge in the rod (before redistribution = after redistribution), you can find the remaining charge at the other end of the rod.

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