What is the Coefficient of Static Friction for Two Tied Objects?

AI Thread Summary
The discussion revolves around calculating the coefficient of static friction and tension between two tied objects with different masses. The coefficient of static friction is determined to be 0.40 based on the maximum static friction force of 31.4N and the combined weight of the objects. When a force of 15N is applied downward on the 3.0kg object, it increases the normal force, thereby affecting the maximum static friction and tension in the string. Participants emphasize that static friction prevents relative motion until a threshold is exceeded, and there is confusion about how to approach the calculations for the scenario where force is applied. Overall, the thread highlights the complexities of static friction and the need for careful consideration of forces involved.
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Homework Statement


Two objects are made of identical material and are tied together with string. The first object has a mass of 5.0kg and the second object has a mass of 3.0kg. Students measure the maximum force of static friction as 31.4N to move both objects across a horizontal surface.
a) What is the coefficient of static friction?
b) What is the magnitude of the tension in the string if they pull on the first object?
c) A student pushes the 3.0kg object with a force of 15.0[down]. What are the magnitudes of the maximum force of static friction and the tension now?
d) Will your answers to (c) change if the student pushes down on the 5.0kg object instead? Explain.

Homework Equations



The Attempt at a Solution


a) μs=Fs / Fn
=31.4 / (8)(9.8)
μs= 0.40

b) To solve B) I came up with two equations, one for each object and equated them to solve for acceleration, and tension.

Fs-Ft=ma
31.4-Ft=5a
Ft=31.4-5a
Ft= 11.78N <-- I found this by finding the acceleration first, and subbing it into 31.4-5a

Ft=ma
31.4-5a=3a
31.4=8a
a=2.925m/s2

c)

d)

I know how to solve a) b) but I have no clue how to solve c). How would I go about doing it?
 
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oMovements said:
b) To solve B) I came up with two equations, one for each object and equated them to solve for acceleration, and tension.
What acceleration? This is still the static case.

For c, what is the normal force from the surface on the 3kg block now? (Is the 15 in Newtons or kg-weight?)
 
oMovements said:
b) To solve B) I came up with two equations, one for each object and equated them to solve for acceleration, and tension.

Fs-Ft=ma
31.4-Ft=5a
Ft=31.4-5a
Ft= 11.78N <-- I found this by finding the acceleration first, and subbing it into
It is probably best not to do it that roundabout way, because you are assuming that coefficient of kinetic friction is going to be equal to the coefficient of static friction and you know, in principle, this is almost never true.

All you need to consider is that the 3kg object (with μs=0.4) is being dragged by the string. Find the max tension in the string.

I know how to solve a) b) but I have no clue how to solve c). How would I go about doing it?
In part (c), someone is pushing down on the object, increasing the normal force between the object and the surface it sits on. You need to now find the increased tangential friction force.
 
haruspex said:
What acceleration? This is still the static case.

For c, what is the normal force from the surface on the 3kg block now? (Is the 15 in Newtons or kg-weight?)

15N. There is an acceleration because the it states "Students measure the maximum force of static friction as 21.4N to move both objects across a horizontal surface." and static friction can also cause an object to move if I remember correctly.
 
NascentOxygen said:
It is probably best not to do it that roundabout way, because you are assuming that coefficient of kinetic friction is going to be equal to the coefficient of static friction and you know, in principle, this is almost never true.

All you need to consider is that the 3kg object (with μs=0.4) is being dragged by the string. Find the max tension in the string.In part (c), someone is pushing down on the object, increasing the normal force between the object and the surface it sits on. You need to now find the increased tangential friction force.

What other way can I solve the tension in the string without equating the 2 equations? I still got the correct answer using this method by the way.

I'm also still confused how to solve c)
 
Last edited:
With what force is the 3kg block in (c) pushing down onto the table?
 
NascentOxygen said:
With what force is the 3kg block in (c) pushing down onto the table?

Force of 15N
 
oMovements said:
Force of 15N
What force was the 3kg block exerting on the table before the student pressed down on it? What do you think that force will increase by when the student presses down?
There is an acceleration because the it states "Students measure the maximum force of static friction as 21.4N to move both objects across a horizontal surface."
That's the force required to overcome static friction. Until it is overcome there is no acceleration.
and static friction can also cause an object to move if I remember correctly.
Yes, but it cannot cause the object to move relative to the surface. Friction always opposes relative motion of the surfaces in contact.
 
oMovements said:
Force of 15N
Plus its weight!
 
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