What is the Conservation of Energy Principle in Bungee Jumping?

AI Thread Summary
The discussion focuses on applying the conservation of energy principle to determine the speed of a bungee jumper at a height of 12.5 m above the water. The jumper has a mass of 64.5 kg and starts from a platform 48.0 m high, with a bungee cord length of 10.1 m and a force constant of 65.5 N/m. The key equations used include kinetic energy (Ek), gravitational potential energy (Ep), and elastic potential energy (Ee). Participants clarify that the correct height for calculations is 35.5 m, as the jumper has not descended the full 48 m, and the appropriate stretch of the bungee cord must also be considered. The final consensus confirms the correct height and stretch values for accurate calculations.
jasonbans
Messages
45
Reaction score
0

Homework Statement


A bungee jumper of mass 64.5 kg (including safety gear) is
standing on a platform 48.0 m above a river. The length of
the unstretched bungee cord is 10.1 m. The force constant
of the cord is 65.5 N/m. The jumper falls from rest and just
touches the water at a speed of zero. The cord acts like an
ideal spring. Use conservation of energy to determine the
jumper’s speed at a height of 12.5 m above the water on
the first fall.

Homework Equations


Ek=1/2mv^2
Ep=mgh
Ee=1/2kx^2

The Attempt at a Solution


so i did mgh = 1/2mv^2 + 1/2kx^2 and solve for v but somehow i am not getting the answer 6.3m/s
 
Physics news on Phys.org
jasonbans said:

Homework Statement


A bungee jumper of mass 64.5 kg (including safety gear) is
standing on a platform 48.0 m above a river. The length of
the unstretched bungee cord is 10.1 m. The force constant
of the cord is 65.5 N/m. The jumper falls from rest and just
touches the water at a speed of zero. The cord acts like an
ideal spring. Use conservation of energy to determine the
jumper’s speed at a height of 12.5 m above the water on
the first fall.

Homework Equations


Ek=1/2mv^2
Ep=mgh
Ee=1/2kx^2

The Attempt at a Solution


so i did mgh = 1/2mv^2 + 1/2kx^2 and solve for v but somehow i am not getting the answer 6.3m/s

You may have substituted in some incorrect values, or you may have "mis-used" you calculator.

Show us your substitution / simplifications so we can see what went wrong.
 
this is what i did
 

Attachments

  • asgadgha.jpg
    asgadgha.jpg
    20.3 KB · Views: 404
jasonbans said:
this is what i did

Two problems:

When 12.5 m above the water, the jumper has not descended 48m, so you h value is not appropriate, and the bungee has not been stretched 12.5 m, so your x value is not appropriate.
 
12.5 above the water meaning 48 subtract 12.5 = 35.5m for the height?
i don't know how much it stretched by am i suppose to calculate it?
 
thx got the answer now
 
Last edited:
jasonbans said:
is the height 35.5 m and it stretched 25.5m right?

if it was 10.0 m long to start with it will have stretched 25.5m

edie: the h value is 35.5, yes. best called the change in height.
 
Back
Top