What is the Correct Calculation for Jack's Homemade Temperature Scale?

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SUMMARY

Jack's homemade temperature scale is based on an uncalibrated mercury thermometer that reads 20.0S in an ice-water bath and 170S above boiling water. He divides the distance between these two readings into 150 equal parts. To convert a reading of 95S on Jack's scale to Celsius, the correct calculation yields 75C, contrary to the initial incorrect answer of 50C. The equation used for conversion, T = (xT - x0)/(x100 - x0) x 100, was identified as incomplete, leading to confusion in the solution process.

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Homework Statement



Jack decides to create his own temperature scale. He places an uncalibrated mercury thermometer into an ice-water bath and records the mercury level as 20.0S. He then places the same thermometer above boiling water and records the mercury level as 170S. Finally, he divides the distance between these two levels into 150 equal lengths.

Calculate the reading on a Celsius thermometer when Jack's thermometer reads 95S.

Homework Equations



I used temperature, T = (xT - x0)/(x100 - x0) x 100.

The Attempt at a Solution



My answer is 50C. But the correct answer is 75C. Can anyone kindly help please?
 
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Is the problem statement exactly as you've transcribed it?
 
By Bystander! Unfortunately, yes. Thanks for replying!
 
Your equation (2. Relevant Eqtns.) is incomplete/ambiguous, but your answer is what I get. This has the "look" of problems that are re-cycled from year to year, or class to class, and frequently posted/assigned without proper proof-reading whenever the numbers are changed.
 
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