What Is the Correct Calculation for Satellite Speed in a Stable Orbit?

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Homework Help Overview

The discussion revolves around calculating the speed of a satellite in a stable circular orbit, specifically focusing on the relationship between centripetal acceleration and gravitational force. The problem involves using the universal gravitational constant and the mass of the Earth, with a specified orbital radius.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants explore the relationship between centripetal acceleration and gravitational force, questioning how to derive the satellite's speed from given parameters. There are attempts to manipulate equations involving acceleration and gravitational force, with some participants expressing confusion over the correct application of these equations.

Discussion Status

The discussion is active, with participants sharing various approaches and questioning assumptions about the relationships between variables. Some guidance has been offered regarding the use of gravitational force and centripetal acceleration equations, but there is no explicit consensus on the correct method yet.

Contextual Notes

Participants note the importance of unit conversion, specifically the need to convert the orbital radius from kilometers to meters, which has caused confusion in calculations. There are also references to the proportional relationship between acceleration and radius, which some participants are interpreting differently.

BitterSuites
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[SOLVED] Centripetal Acceleration

Homework Statement



In order for a satellite to move in a stable circular orbit of radius 6689 km at a constant speed, its centripetal acceleration must be inversely proportional to the square of the radius of the orbit.

What is the speed of the satellite? The universal gravitational constant is 6.67259e-11 and the mass of the Earth is 5.98e24.

Answer in units of m/s.

Homework Equations



a = v^2/r
F = Gm1m2/r^2
F = ma

The Attempt at a Solution



Ok, a = v^2/r becomes v = sqrt of ar.

From the problem, a = r^-1/2 (or am I wrong?) so a = .012227

sqrt of ar = sqrt of 81.9863
v=9.0-4358

This however, is incorrect. Somehow G is important, but I'm not seeing it. Please help lead me to the right equations.
 
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Centripetal acceleration=force of gravity

(m2)(v^2/r)=(G*m1*m2)/r^2

You can find acceleration from there.
 
I already have acceleration from r=-1/2 as told from the problem itself. I need to solve for v. Can I use the above equation if I don't know v or m1?
 
There is only one force acting on the satellite, the force of gravity. You know that [tex]F_g=\frac{GMm}{r^2}[/tex].

By Newton's 2nd you also know that [tex]\sum F=ma[/tex] .

Now ask yourself how you can use this along with what you were given to find v.
 
Last edited:
BitterSuites said:
From the problem, a = r^-1/2 (or am I wrong?) so a = .012227

Yes, you're right - you're wrong! :smile:

The question is telling you that a is proportional to r^-1/2. All it means is that a = F/m, and F is proportional to r^-1/2, so a must be also.

This is a questioner intending to be helpful, but actually being a little confusing.

Your "relevant equations" are correct, so just solve them (and ignore the help). :smile:
 
mv^2/r =GMm/r^2
v^2=GM/r^2
v= sqrt GM/r^2

GM=gRe^2 as well
 
Ok, so I did it this way and still ended up with the incorrect answer. Where am I still messing up?

F=Gm1m1/r^2
9.8 = 6.67259e-11*M*5.98e24/6689^2
4.38471e8=6.67259e-11*M*5.98e24
7.33242e-17=6.67259e-11*M
M=.000001

F=ma
9.8=.000001a
a = 8.91812e6

a=v^2/r
8.91812e6 = v^2/6689
v^2=5.96533e10
v=244240

So where did I go wrong again? :D
 
BitterSuites said:
Ok, so I did it this way and still ended up with the incorrect answer. Where am I still messing up?

F=Gm1m1/r^2
9.8 = 6.67259e-11*M*5.98e24/6689^2
4.38471e8=6.67259e-11*M*5.98e24
7.33242e-17=6.67259e-11*M
M=.000001

F=ma
9.8=.000001a
a = 8.91812e6

a=v^2/r
8.91812e6 = v^2/6689
v^2=5.96533e10
v=244240

So where did I go wrong again? :D
it's 6689km... not 6689m
 
I tried v = sqrt GM/r^2 and it is also incorrect.
 
  • #10
mysqlpress said:
it's 6689km... not 6689m

Wow. I'm special. Let me throw that in and see what happens :D
 
  • #11
BitterSuites said:
I tried v = sqrt GM/r^2 and it is also incorrect.
it's my typo
should be v=sqrt GM/R

you see, from my deviation :)
 
  • #12
Phew. On the last try I got it correct. My calculations above worked once I converted km to m. *judges himself harshly*

v = sqrt GM/r^2 didn't work even with the km converted to m.
 
  • #13
Ah :) Thanks for everyone's help! I'm marking it solved now.
 

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