What Is the Correct Calculation for Satellite Speed in a Stable Orbit?

AI Thread Summary
To calculate the speed of a satellite in a stable circular orbit, centripetal acceleration must be considered, which is inversely proportional to the square of the orbit's radius. The relevant equations include F = Gm1m2/r^2 and a = v^2/r. A user initially struggled with the calculations, mistakenly using incorrect units and formulas. After correcting the radius from kilometers to meters, the calculations aligned correctly, leading to the correct speed. The discussion emphasizes the importance of unit conversion and proper application of gravitational formulas in orbital mechanics.
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[SOLVED] Centripetal Acceleration

Homework Statement



In order for a satellite to move in a stable circular orbit of radius 6689 km at a constant speed, its centripetal acceleration must be inversely proportional to the square of the radius of the orbit.

What is the speed of the satellite? The universal gravitational constant is 6.67259e-11 and the mass of the Earth is 5.98e24.

Answer in units of m/s.

Homework Equations



a = v^2/r
F = Gm1m2/r^2
F = ma

The Attempt at a Solution



Ok, a = v^2/r becomes v = sqrt of ar.

From the problem, a = r^-1/2 (or am I wrong?) so a = .012227

sqrt of ar = sqrt of 81.9863
v=9.0-4358

This however, is incorrect. Somehow G is important, but I'm not seeing it. Please help lead me to the right equations.
 
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Centripetal acceleration=force of gravity

(m2)(v^2/r)=(G*m1*m2)/r^2

You can find acceleration from there.
 
I already have acceleration from r=-1/2 as told from the problem itself. I need to solve for v. Can I use the above equation if I don't know v or m1?
 
There is only one force acting on the satellite, the force of gravity. You know that F_g=\frac{GMm}{r^2}.

By Newton's 2nd you also know that \sum F=ma .

Now ask yourself how you can use this along with what you were given to find v.
 
Last edited:
BitterSuites said:
From the problem, a = r^-1/2 (or am I wrong?) so a = .012227

Yes, you're right - you're wrong! :smile:

The question is telling you that a is proportional to r^-1/2. All it means is that a = F/m, and F is proportional to r^-1/2, so a must be also.

This is a questioner intending to be helpful, but actually being a little confusing.

Your "relevant equations" are correct, so just solve them (and ignore the help). :smile:
 
mv^2/r =GMm/r^2
v^2=GM/r^2
v= sqrt GM/r^2

GM=gRe^2 as well
 
Ok, so I did it this way and still ended up with the incorrect answer. Where am I still messing up?

F=Gm1m1/r^2
9.8 = 6.67259e-11*M*5.98e24/6689^2
4.38471e8=6.67259e-11*M*5.98e24
7.33242e-17=6.67259e-11*M
M=.000001

F=ma
9.8=.000001a
a = 8.91812e6

a=v^2/r
8.91812e6 = v^2/6689
v^2=5.96533e10
v=244240

So where did I go wrong again? :D
 
BitterSuites said:
Ok, so I did it this way and still ended up with the incorrect answer. Where am I still messing up?

F=Gm1m1/r^2
9.8 = 6.67259e-11*M*5.98e24/6689^2
4.38471e8=6.67259e-11*M*5.98e24
7.33242e-17=6.67259e-11*M
M=.000001

F=ma
9.8=.000001a
a = 8.91812e6

a=v^2/r
8.91812e6 = v^2/6689
v^2=5.96533e10
v=244240

So where did I go wrong again? :D
it's 6689km... not 6689m
 
I tried v = sqrt GM/r^2 and it is also incorrect.
 
  • #10
mysqlpress said:
it's 6689km... not 6689m

Wow. I'm special. Let me throw that in and see what happens :D
 
  • #11
BitterSuites said:
I tried v = sqrt GM/r^2 and it is also incorrect.
it's my typo
should be v=sqrt GM/R

you see, from my deviation :)
 
  • #12
Phew. On the last try I got it correct. My calculations above worked once I converted km to m. *judges himself harshly*

v = sqrt GM/r^2 didn't work even with the km converted to m.
 
  • #13
Ah :) Thanks for everyone's help! I'm marking it solved now.
 
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