What is the Correct Domain of Integration for a Double Integral Problem?

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SUMMARY

The discussion centers on determining the correct domain of integration for a double integral problem involving the area bounded by the curves y=0, y=4-x², and x=1. The user initially plotted the domain and proposed a change in the x domain from 1 to 2 and the y domain from 0 to 4-x². However, there is confusion regarding the upper bound of the first integral, as it is suggested that it should be a function of y rather than x. The correct interpretation of the bounds is crucial for accurate integration.

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  • Understanding of double integrals in calculus
  • Familiarity with polynomial functions and their graphs
  • Knowledge of integration techniques involving variable limits
  • Ability to interpret and analyze graphical representations of functions
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  • Review the concept of double integrals with variable limits in calculus
  • Study the properties of polynomial functions, specifically y=4-x²
  • Learn how to correctly set up integration bounds based on graphical analysis
  • Explore examples of double integrals with non-constant upper limits
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Students studying calculus, particularly those tackling double integrals and integration bounds, as well as educators looking for examples to illustrate these concepts.

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Homework Statement



question 2:
http://www.math.ubc.ca/~haber/courses/math253/Welcome_files/asgn5.pdf"

The Attempt at a Solution



So for part a) I tried to plot my domain of integration and ended up concluding it was an area bounded by y=0, y=4-x^2, and x=1. Is this okay?

In not too sure about part b) I'm just going off the graph here and so if that's wrong this will be wrong. Here is what i did I changed x domain from 1->(4-x^2) to 1->2 and I changed y domain from 0->3 to 0->4-x^2.

Is this correct?

Thanks!
 
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how could we integrate when the upper bound of the first integral is a polynomial x=4-x^2? Maybe I am misunderstanding something. Would it not have to be either a constant or a function of y?
 
The upper limit on the inner integral is surely a typo and probably is supposed to be x = 4 - y2.
 
I sure hope so. Thank you.
 

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