What Is the Correct Induced Charge on an Uncharged Conductor?

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Discussion Overview

The discussion revolves around the induced charge on an uncharged conductor in the presence of an electric field. Participants explore the application of different principles, such as induced charge rules and Gauss's law, to determine the charge density on the conductor's surfaces.

Discussion Character

  • Debate/contested
  • Technical explanation

Main Points Raised

  • One participant argues that the induced charge density on the bottom of the conductor must be -η, with the top having a charge density of η, based on the rule of induced charge.
  • Another participant counters this by applying Gauss's law, concluding that the charge density on the bottom of the conductor is -η/2, which is also supported by a tutor's input.
  • It is noted that the rule of induced charge is typically applicable to grounded conductors, while the current scenario involves an isolated uncharged conductor.
  • A participant expresses confusion about the nature of the question, suggesting it may pertain to a plane configuration.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the correct induced charge density, with competing views presented regarding the application of induced charge rules and Gauss's law.

Contextual Notes

There is a lack of clarity regarding the assumptions made about the conductor's configuration and the conditions under which the rules are applied, particularly the distinction between grounded and isolated conductors.

athrun200
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attachment.php?attachmentid=44393&stc=1&d=1330230514.jpg

The question itself is easy. E field at 2 is zero. E field at other points are of magnitude [itex]\frac{\eta}{2\epsilon}[/itex]

But I am arguing with my classmate and tutor that what is the charge induced on the uncharged conductor.

For me, I simply use the rule induced charge (charge of same magnitude but different sign will be induced) to conclude that the charge density on the bottom of the conductor must be [itex]-\eta[/itex].
Since it is uncharged, the charge density on the top must be [itex]\eta[/itex].

But my classmate use Gauss law and obtain that the charge density on the bottom of the conductor is [itex]\frac{-\eta}{2}[/itex].

My tutor also said that the answer provided by professor is [itex]\frac{-\eta}{2}[/itex].

So why I can't apply the rule of induced cahrge here?
 

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If the charge density on the top of the uncharged conductor was η, the field in region 1 would be η/ε which is not correct.
The rule of induced charge is applicable to grounded conductors. Here the uncharged conductor is isolated.
 
Last edited:
But it seems my question is a plane.
 
athrun200 said:
But it seems my question is a plane.

Sorry, my mistake. I edited the previous reply.
 
Thx a lot
I understand now
 

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