What Is the Correct Induced Charge on an Uncharged Conductor?

Join the discussion
Registration is free. Start your own thread to ask a follow-up.
4 replies · 3K views
athrun200
Messages
275
Reaction score
0
attachment.php?attachmentid=44393&stc=1&d=1330230514.jpg

The question itself is easy. E field at 2 is zero. E field at other points are of magnitude [itex]\frac{\eta}{2\epsilon}[/itex]

But I am arguing with my classmate and tutor that what is the charge induced on the uncharged conductor.

For me, I simply use the rule induced charge (charge of same magnitude but different sign will be induced) to conclude that the charge density on the bottom of the conductor must be [itex]-\eta[/itex].
Since it is uncharged, the charge density on the top must be [itex]\eta[/itex].

But my classmate use Gauss law and obtain that the charge density on the bottom of the conductor is [itex]\frac{-\eta}{2}[/itex].

My tutor also said that the answer provided by professor is [itex]\frac{-\eta}{2}[/itex].

So why I can't apply the rule of induced cahrge here?
 

Attachments

  • 1.JPG
    1.JPG
    27.7 KB · Views: 929
Physics news on Phys.org
If the charge density on the top of the uncharged conductor was η, the field in region 1 would be η/ε which is not correct.
The rule of induced charge is applicable to grounded conductors. Here the uncharged conductor is isolated.
 
Last edited:
athrun200 said:
But it seems my question is a plane.

Sorry, my mistake. I edited the previous reply.