What Is the Curl of a Vector Field and Its Relation to Divergence?

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Homework Help Overview

The discussion revolves around the mathematical concepts of curl and divergence in vector fields, particularly in the context of electromagnetism. Participants are exploring the relationship between these two operations and clarifying their definitions and implications.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants are questioning the nature of the curl of a vector field and its classification as a vector or a vector field. There is an exploration of the implications of taking the divergence of the curl, with some participants attempting to clarify the terminology and relationships involved.

Discussion Status

Some participants are providing insights into the properties of curl and divergence, while others are seeking clarification on specific terms and concepts. There is an acknowledgment of misunderstandings regarding the nature of the curl and its relationship to vector fields.

Contextual Notes

Participants are operating under the assumption that the curl of a vector field yields a vector field, and there is a discussion about the implications of this in relation to the divergence operation. The conversation reflects a mix of established knowledge and points of confusion that require further exploration.

fluidistic
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Homework Statement


For example in electromagnetism and I think it's true for any vector field, the relation \vec \nabla \cdot (\vec \nabla \times \vec E)=0.
As far as I know, the curl of a vector field is a vector. So basically the above expression takes the divergence of a vector? It can't be so. It means that the curl of a vector field is not a vector but a vector field.

It sounds very strange to me... can anyone shred some light on this please?
 
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My 2 cents - The curl of a vector field, being a cross product, is a vector perpendicular to the field and so the dot product outside would naturally be zero, coz perpendicular vectors have a zero dot product...?
 
SVXX said:
My 2 cents - The curl of a vector field, being a cross product, is a vector perpendicular to the field and so the dot product outside would naturally be zero, coz perpendicular vectors have a zero dot product...?

I appreciate your help, however I have some questions.
What do you mean by "dot product outside"? Dot product between what vectors?

I'm taking a divergence. Written differently I have div(curl (E))=0.
I've been taught that the curl of a vector field is a vector and I've been taught that the divergence applies to vector fields, not vectors. I'm not asking why the divergence of the curl of a vector field is worth 0, but a clarification of the divergence/curl in this special case.
 
fluidistic said:
I appreciate your help, however I have some questions.
What do you mean by "dot product outside"? Dot product between what vectors?

I'm taking a divergence. Written differently I have div(curl (E))=0.
I've been taught that the curl of a vector field is a vector and I've been taught that the divergence applies to vector fields, not vectors. I'm not asking why the divergence of the curl of a vector field is worth 0, but a clarification of the divergence/curl in this special case.

You can only take the curl of a vector field which yields a vector field.

For a vector field A this is:
[URL]http://upload.wikimedia.org/math/c/5/d/c5df8cb34c3b1480237b941f46628338.png[/URL] =
[URL]http://upload.wikimedia.org/math/a/5/9/a59969f3cc771bae6bf56bcf001aeb3d.png[/URL]
The x, y, and z with the hats on them represent the unit vectors in each direction.

If you take the divergence from this curl, this will always result in 0.
This is not trivial to think up, but if you fill everything in, you'll see that it works out.
This results in:
[URL]http://upload.wikimedia.org/math/b/8/3/b839f27612baaf13dca6770ef8f798fe.png[/URL]
 
Last edited by a moderator:
Ok thanks a lot Serena liker. I erroneously thought that the curl of a vector field was a vector, instead of a vector field.
Now this makes perfect sense.
 

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