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What is the definite integral of 1/(36+x^2) with bounds [0, 6]?

I've only been taught U substitution to handle problems like these. I let u = 36+x^2 and du=2xdx but I am stuck and don't know what to do. Te answer is pi/24 but I don't know how to obtain it.

Is there a better u to choose? if so, what?

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# Homework Help: What is the definite integral of 1/(36+x^2) with bounds [0, 6]

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