What is the derivative of f(t) when integrated with inverse trig functions?

[shinkansenfan]

If f(t)=integral of 1/(1+x^2) from t^2 to 0,then f'(t)=?

thanks very much.

 

[mathman]

The integral looks odd since t^2 > 0 and you have 0 as the upper limit.. However as it stands, f'(t)=-2t/(1 + t^4)

 

[jtyler05si]

Use integration of inverse trig functions.