What is the determinant of a Lorentz transformation matrix?

  • Context: Graduate 
  • Thread starter Thread starter vin300
  • Start date Start date
  • Tags Tags
    Determinant Matrix
Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
3 replies · 6K views
vin300
Messages
602
Reaction score
4
I have been asked to prove that the determinant of any matrix representing a Lorentz transformation is plus or minus 1. I can see that the determinant of the Lorentz transformation matrix is 1, but don't know how to prove +-1 in general. How to generalise the lorentz transformation? I've also read that rotations in the spatial planes also constitute L.T., that any transformation that keeps the metric invariant is an L.T.
 
on Phys.org
Since any arbitrary LT is either a boost between timelike and spacelike directions, a rotation between spacelike directions, or a combination of the two, I think all you need is to check that the determinant of a 3D rotation is [itex]\pm 1[/itex]. After that, if [itex]\underline L \underline R[/itex] both represent LT's, then what do you know about

[tex]\det (\underline L \underline R) = ?[/tex]
 
Reversal of the space or time axis produces a matrix of determinant -1. That proves that any LT matrix has determinant [itex]\pm 1[/itex]. det(LR)=det(L)det(R), so again, the resulting matrix has determinant [itex]\pm 1[/itex].
 
Last edited:
How to prove that the matrix version of ηa'b'= Ama'Anb'ηmn is η= ATηA, where A is an LT matrix?