The discussion revolves around a physics problem involving a car moving down a slope with a specific grade and constant speed. The participants are examining the frictional force acting on the car, its direction, and magnitude, while considering the effects of gravitational forces and the absence of a coefficient of friction.
The discussion is active, with participants exploring different interpretations of the problem. Some have proposed steps to approach the solution, while others are clarifying concepts related to friction and gravitational forces. There is no explicit consensus on the final solution, but guidance has been offered regarding the analysis of forces.
Participants note the absence of the coefficient of friction and discuss its implications for solving the problem. The constant speed of the car is also a focal point in understanding the forces at play.
jimmyboykun said:ok, but what about the 11m/s, does that velocity come into play?
Not a big deal, but arctan(.14) ~= 7.97.jimmyboykun said:ok so I solved the problem, and this is what I did: m*g*sin(7.96) the 7.96 is the reverse tangent.
That formulation can confuse people when thinking about e.g. a car being driven up a slope. It leads them to think that the friction between road and tyre would act down the slope. Better always to write that friction opposes relative motion of the surfaces in contact.Legaldose said:The frictional force always opposes the motion,
jimmyboykun said:thanks, but what about the solution that I solved 2,989N is that solution the magnitude and direction, or if there is there still more?