What is the direction of torque for a sin curve?

Click For Summary
SUMMARY

The discussion clarifies the direction of torque represented by a sine wave function, T=sin(x), where x ranges from 0 to 2π. Torque is considered positive in the range 0 < x < π, indicating a clockwise direction, while it becomes negative for π < x < 2π, indicating an anticlockwise direction. The right-hand rule is confirmed as the definitive method for determining torque direction. The conversation concludes with an affirmation of understanding regarding the torque's behavior across the sine curve.

PREREQUISITES
  • Understanding of torque and its units (length x force)
  • Familiarity with trigonometric functions, specifically sine waves
  • Knowledge of the right-hand rule for determining rotational direction
  • Basic grasp of the unit circle and its applications in physics
NEXT STEPS
  • Study the applications of the right-hand rule in rotational dynamics
  • Explore torque calculations in various mechanical systems
  • Learn about the relationship between angular displacement and torque
  • Investigate the effects of varying amplitude and frequency on torque in oscillatory systems
USEFUL FOR

Physics students, mechanical engineers, and anyone interested in understanding rotational dynamics and torque behavior in sinusoidal functions.

zealous131
Messages
4
Reaction score
0
Hi, I want to clear my concept about the direction of torque for a sin curve. Assume the torque can be represented by a sin wave (T=sinx, where x is from 0 to 2π and it starts from the origin(0,0) with an amplitude of 1.

My understanding of the torque direction is as follows (assumuing clockwise torqe to be positive):

1- from 0 to the first maxima (0≤T≤1), torque was increasing and its direction was positive.
2- from first maxima, the direciton of the torque becomes anticlockwise until it reashces the first minima. (i.e. for 1≤T≤-1 torque is anti-clockwise)
3- From the first minima until the zero crossing, the direction of the torque becomes clockwise again.i.e. (-1≤T≤1, torque is clockwise again).

Please comment if I am right or wrong and suggest me the true direction sense for this particular case.

Many thanks for your help!
 
Physics news on Phys.org
First of all, sin(x) is unitless, while torque has units of length x force; e.g., meter-Newtons.
Torque is positive; 0 < x < π
Torque is negative; π < x < 2π
The right hand rule determines direction of torque.
 
Thanks Bob! Its clear now, really appreciate your help!
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 11 ·
Replies
11
Views
3K
  • · Replies 31 ·
2
Replies
31
Views
5K
Replies
14
Views
2K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 76 ·
3
Replies
76
Views
7K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 28 ·
Replies
28
Views
3K
  • · Replies 22 ·
Replies
22
Views
5K
  • · Replies 11 ·
Replies
11
Views
2K