What is the direction of torque for a sin curve?

AI Thread Summary
The discussion centers on understanding the direction of torque represented by a sine wave, specifically T=sin(x) from 0 to 2π. It is clarified that torque is positive when x is between 0 and π, indicating a clockwise direction, and negative from π to 2π, indicating an anticlockwise direction. The right-hand rule is emphasized as the method for determining torque direction. The original poster's understanding of torque direction is confirmed as correct with some additional clarification. Overall, the conversation effectively resolves the query about torque direction in relation to the sine curve.
zealous131
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Hi, I want to clear my concept about the direction of torque for a sin curve. Assume the torque can be represented by a sin wave (T=sinx, where x is from 0 to 2π and it starts from the origin(0,0) with an amplitude of 1.

My understanding of the torque direction is as follows (assumuing clockwise torqe to be positive):

1- from 0 to the first maxima (0≤T≤1), torque was increasing and its direction was positive.
2- from first maxima, the direciton of the torque becomes anticlockwise until it reashces the first minima. (i.e. for 1≤T≤-1 torque is anti-clockwise)
3- From the first minima until the zero crossing, the direction of the torque becomes clockwise again.i.e. (-1≤T≤1, torque is clockwise again).

Please comment if I am right or wrong and suggest me the true direction sense for this particular case.

Many thanks for your help!
 
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First of all, sin(x) is unitless, while torque has units of length x force; e.g., meter-Newtons.
Torque is positive; 0 < x < π
Torque is negative; π < x < 2π
The right hand rule determines direction of torque.
 
Thanks Bob! Its clear now, really appreciate your help!
 
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