What is the distance between two parallel planes?

Click For Summary
SUMMARY

The distance between two parallel planes can be calculated using their equations. For the planes defined by the equations x + y + 2z = 4 and 2x + 2y + 4z + 11 = 0, the distance can be derived from the coefficients of the variables. Additionally, the general formula for the distance between two parallel planes ax + by + cz + d1 = 0 and ax + by + cz + d2 = 0 is given by the formula |d2 - d1| / √(a² + b² + c²). To find parallel planes that are 2 units away from the plane 2x - y + 2z = 5, one can adjust the constant term in the equation accordingly.

PREREQUISITES
  • Understanding of plane equations in three-dimensional space
  • Familiarity with the concept of distance between geometric entities
  • Knowledge of linear algebra, specifically vector operations
  • Ability to manipulate algebraic equations
NEXT STEPS
  • Study the derivation of the distance formula between parallel planes
  • Learn how to find points on a plane from its equation
  • Explore the concept of normal vectors and their role in determining distances
  • Investigate the implications of plane equations in higher dimensions
USEFUL FOR

Students studying geometry, mathematics educators, and anyone interested in understanding the properties of planes in three-dimensional space.

385sk117
Messages
50
Reaction score
0

Homework Statement



1. Find the distance betwwen the parallel palnes:

a) x + y + 2z = 4 and 2x + 2y + 4z +11 = 0
b) ax + by + cz + d1 = 0 and ax + by + cz + d2 = 0

2.Find the equations of the two planes which are parallel to 2x - y + 2z = 5 and 2 unit from it

Homework Equations




The Attempt at a Solution



I think i should find any point on one of the plane and using that to find the perpendicular line between two planes which will give the distance between them, but how can i find a point on the plane from the equation given to me?
 
Physics news on Phys.org
Pick any x and y you want, plug them into the equation for the plane and then solve for z, and you will have a point on the plane.
 
oh, so if there isn't any restriction then i can choose any value of x and y on the plane?
Thankyou :)
 
385sk117 said:
oh, so if there isn't any restriction then i can choose any value of x and y on the plane?
Thankyou :)

Well since no restrictions have been made on the planes, they "stretch" over every possible x and y value. Its a bit like a line in the x-y plane; Unless its domain has been restricted, it will cross over every single real x value and have a corrosponding y value there.
 

Similar threads

Replies
17
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 6 ·
Replies
6
Views
5K
  • · Replies 3 ·
Replies
3
Views
7K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
8
Views
3K
  • · Replies 7 ·
Replies
7
Views
2K