MHB What is the Dot Product of u+v?

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The discussion centers around calculating the dot product of the vectors u and v, specifically (u + v)·(2u + 5v). The correct calculation shows that u + v equals <1, -1> and 2u + 5v equals <11, -14>. When these vectors are dotted together, the result is 25, which aligns with the book's answer. Participants note the importance of distinguishing between dot and cross products, as they yield different results. The conversation also touches on formatting issues for representing the dot product in titles.
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$$u=\left\langle - 2,3\right\rangle v=\left\langle 3,-4 \right\rangle$$
$$\left(u+v\right)\cdot\left(2u+5v\right)=\left\langle 11,14 \right\rangle$$

But the book answer is 25?
 
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karush said:
$$u=\left\langle - 2,3\right\rangle v=\left\langle 3,-4 \right\rangle$$
$$\left(u+v\right)\cdot\left(2u+5v\right)=\left\langle 11,14 \right\rangle$$

But the book answer is 25?
It looks like you stopped somewhere in the middle, but there's a sign error.

The dot product produces a scalar and you have a vector. Let's take a look.
u + v = <1, -1> and 2u + 5v = <11, -14>. Now dot these together.

-Dan

Addendum: Your thread title is (u + v) x (2u + 5v). There is another vector product called the cross product and is written A x B. Try to avoid the x's. The cross product here gives a vastly different answer.
 
Yes, it was dot product 🐴

Not sure how to put the dot in the title.
 
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karush said:
Yes, it was dot product 🐴

Not sure how to put the dot in the title.
There are two options I've seen. The first is to write x dot y. The second is to write x.y

-Dan
 
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