StarPhysics
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Homework Statement
We have a chain of 10 blocks, all of them joined by a thin rope and placed in a straight line.
Suddenly, other two blocks collide with v speed at one end with the chain of the 10 blocks.
It is assumed that the table is frictionless and the collision is elastic.
The main question is: after the colission, which blocks are going to move and at what speed?.
Homework Equations
Since we have an elastic collision, we have to take into account the following equations: P_{i}=P_{f} \rightarrow m_{1}v_{1i}+...+m_{n}v_{ni}=m_{1}v_{1f}+...+m_{n}v_{nf}
Moreover, the colission is completely elastic, which means: E_{k(i)}=E_{k(f)}
The Attempt at a Solution
Initially, the velocity of the blocks of the chain is zero, which means that the linear momentum is the following one: P_{i}=mv+mv=2mv.
We also know that the collision is elastic, and, therefore, (all the blocks have the same weight), the final velocity of the whole system, should be exactly 2v (please, correct me if I am wrong)
However, then, I have to calculate P_{f}=m(v_{1}+...+v_{12}), but I don't see how to calculate the relation between all the velocities... In other words, I have the following system:
P_{i}=P_{f} \rightarrow 2v=v_{1} + ... + v_{12}
E_{k(i)}=E_{k(b)} \rightarrow 2v=v_{1} + ... +v_{12}
I post an image so that you can get an idea about how the collision is.
Thanks.