What Is the Effective Resistance of Headlights in a Car Battery Circuit?

  • Thread starter Thread starter dblanche
  • Start date Start date
  • Tags Tags
    Resistance
Click For Summary

Homework Help Overview

The discussion revolves around calculating the effective resistance of headlights in a car battery circuit. The problem involves a car battery with a specified voltage and internal resistance, and it examines the voltage drop when the headlights are activated.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants express confusion about the concept of effective resistance versus normal resistance. Some suggest considering the battery as a voltage source in series with its internal resistance to analyze the circuit.

Discussion Status

The discussion includes attempts to clarify the relationship between effective and normal resistance, with some participants providing hints about analyzing the circuit. However, there is no explicit consensus or resolution yet.

Contextual Notes

Participants are encouraged to work through the problem independently, as direct answers are not provided. There is a focus on understanding the underlying concepts rather than simply obtaining a solution.

dblanche
Messages
5
Reaction score
0
I can't seem to get this one, I just don't know how to calculate the effective resistance, what is the difference between effective resistance and normal resistance??

Here is the question:


A car battery has a source voltage of 12.00 V and an internal resistance of
0.015 Ω. When the headlights are turned on (while the engine is not running)
the output voltage of the battery drops to 11.75 V. The effective resistance of
the headlights is nearest to:



If someone could just give me a formula or some hints...that would be great!
 
Physics news on Phys.org
dblanche said:
I can't seem to get this one, I just don't know how to calculate the effective resistance, what is the difference between effective resistance and normal resistance??

Here is the question:


A car battery has a source voltage of 12.00 V and an internal resistance of
0.015 Ω. When the headlights are turned on (while the engine is not running)
the output voltage of the battery drops to 11.75 V. The effective resistance of
the headlights is nearest to:
Think of the battery as a pure source of 12V in series with a .015 Ω resistor. At the current drawn when the headlight is connected, the voltage drop across the resistor is .25V. Work out that current and determine what the resistance of the headlight is.

The effective resistance is the same as the normal resistance.

AM
 
hello,may i know what the answer?
 
chai940610 said:
hello,may i know what the answer?
Welcome to PF. The short answer is NO. You have to try to work it out first.

AM
 

Similar threads

Replies
4
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 8 ·
Replies
8
Views
4K
  • · Replies 8 ·
Replies
8
Views
13K
Replies
2
Views
2K
Replies
14
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 10 ·
Replies
10
Views
4K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 25 ·
Replies
25
Views
3K