SUMMARY
The energy of a photon with a wavelength of 0.10 μm is calculated using the formula E = hc/λ, where h is Planck's constant (6.626 x 10^-34 J·s) and c is the speed of light (3.00 x 10^8 m/s). This results in an energy of approximately 1.24 x 10^-15 Joules. For part (b), electrons must be accelerated through a potential difference that corresponds to their de Broglie wavelength, which is equal to the aperture diameter of 0.10 μm. This indicates that the potential difference required is directly related to the wavelength of the electrons.
PREREQUISITES
- Understanding of photon energy calculations using E = hc/λ
- Familiarity with de Broglie wavelength concept
- Knowledge of electron acceleration in electric fields
- Basic principles of wave-particle duality
NEXT STEPS
- Research the calculation of photon energy using different wavelengths
- Explore the de Broglie wavelength formula for particles
- Study the effects of potential difference on electron acceleration
- Investigate wave-particle duality and its implications in quantum mechanics
USEFUL FOR
Students in physics, particularly those studying quantum mechanics, as well as educators and anyone interested in the wave-particle duality of electrons and photons.