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Galactium
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Homework Statement
You would like to put a solar hot water system on your roof, but you're not sure it's feasible. A reference book on solar energy shows that the ground-level solar intensity in your city is 750 W/m^2 for at least 5 hours a day throughout most of the year.
Assuming that a completely black collector plate loses energy only by radiation, and that the air temperature is 20 ∘C, what is the equilibrium temperature of a collector plate directly facing the sun? Note that while a plate has two sides, only the side facing the sun will radiate because the opposite side will be well insulated.
Homework Equations
dQ/dt=eσAT^4
T=(T_h^4-T_c^4)
e=5.67E-8 W/m^2*K[/B]
The Attempt at a Solution
[/B]
Okay, so I know that Power is equivalent to dQ/dt. The emissivity(e) is equal to 1 because it is an ideal black collector plate. However, the question does not have the dimensions of the plate, so I am assuming it is 1. I know that I have to find the Hot temperature.
P=eσA(T_h^4-T_c^4)
P=eσAT_h^4-eσAT_c^4
P+eσAT_c^4=eσAT_h^4
P+eσAT_c^4/(eσA)=eσAT_h^4
(P+eσAT_c^4/(eσA))^1/4=T_h
OR
T=((P/Aeσ)+T_c^4)