Drain Brain
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is there an equivalent identity for $\sin^2\omega t?$
please tell me.REGARDS!
please tell me.REGARDS!
MarkFL said:It depends on what you want the identity to be in terms of...two identities that spring to mind are:
$$\sin^2(\theta)=1-\cos^2(\theta)$$
$$\sin^2(\theta)=\frac{1-\cos(2\theta)}{2}$$
Drain Brain said:I'm familiar with what you've posted. But $\sin^2(\omega t)$ doesn't fit the form of just $sin^2(\theta)$. I'm confused, how am I suppose to use those identities above?
Drain Brain said:I'm familiar with what you've posted. But $\sin^2(\omega t)$ doesn't fit the form of just $sin^2(\theta)$. I'm confused, how am I suppose to use those identities above?