What is the Equivalent Resistance and Current in this Electrical Circuit?

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SUMMARY

The discussion focuses on calculating the equivalent resistance and current in a circuit with resistors R1 = 85.8 Ω, R2 = R3 = 67.5 Ω, and R4 = 89.7 Ω, powered by a 6.0 V ideal battery. The equivalent resistance is determined by combining R2, R3, and R4 in parallel, followed by adding R1 in series. The currents through each resistor can be calculated using Kirchhoff's laws and Ohm's Law, ensuring accurate analysis of the circuit's behavior.

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Homework Statement


In Fig. 27-29, R1 = 85.8 Ω, R2 = R3 = 67.5 Ω, R4 = 89.7 Ω, and the ideal battery has emf ε = 6.0 V. (a) What is the equivalent resistance? What is i in (b) resistance 1, (c) resistance 2, (d) resistance 3, and (e) resistance 4?

http://edugen.wiley.com/edugen/courses/crs1141/art/qb/qu/c27/Fig27_42.gif



Homework Equations



I in = I out

The Attempt at a Solution



I don't even know where to begin with this problem. I can't figure out how to use the formula of I in = I out with this problem.
 
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For a)

you can see R2, R3, and R4 are all in parallel, so you can find an equivalent resistance for those three, and R1 is in series with that equivalent resistor, so you can find the equivalent resistance. Does that get you going?

The second part asking for the currents can be done with Kirchoff's laws and Ohm's Law
 
R2, R4, & R3 are in parrallel, find the equivilent R for those separate, then take what you got for that and then find the equivilent R for a series using what you got before as well as R1. That should get you started with the first part.

Whoops, looks like someone beat me to it. :)
 

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