What is the Equivalent Resistance in a Series Circuit?

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SUMMARY

The discussion focuses on calculating the equivalent resistance in a series circuit involving resistors R1, R2, R3, and R4. The correct approach involves recognizing that R2 and R3 are in series, resulting in a combined resistance of 4Ω, which is then in parallel with R4. The final equivalent resistance (Re) is determined using the formula 1/Re = 1/4Ω + 1/2Ω + 1/2Ω, leading to Re = 4Ω/5. Participants emphasize the importance of correctly identifying series and parallel connections to solve the problem accurately.

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  • Understanding of series and parallel resistor configurations
  • Basic knowledge of Ohm's Law
  • Familiarity with calculating equivalent resistance
  • Ability to interpret circuit diagrams
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  • Study the principles of series and parallel circuits in depth
  • Learn how to draw and analyze circuit diagrams
  • Explore advanced techniques for calculating equivalent resistance
  • Practice problems involving multiple resistors in various configurations
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Students studying electricity and physics, electrical engineering learners, and anyone seeking to understand circuit analysis and equivalent resistance calculations.

Dr.Phy
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Hi guys,I'm new here and maybe I'm posting this homework in a wrong part of the forum.I tried to find the equivalent resistance.It may be a simple homework but I am learning first for the electricy physic.I tried to find Re first R2+R3=4 Ω and than found Re=1/4 Ω + 1/2 Ω + 1/2 Ω can i slove it this way? (P.s sorry for my bad english.)
 

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Dr.Phy said:
Hi guys,I'm new here and maybe I'm posting this homework in a wrong part of the forum.I tried to find the equivalent resistance.It may be a simple homework but I am learning first for the electricy physic.I tried to find Re first R2+R3=4 Ω and than found Re=1/4 Ω + 1/2 Ω + 1/2 Ω can i solve it this way? (P.s sorry for my bad english.)


R1 is not parallel with the resultant of R2, R3, R4. Check.

ehild
 
Can it be formed so?
 

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Dr.Phy said:
Can it be formed so?

Yes. :smile:

ehild
 
ehild said:
Yes. :smile:

ehild
Then I did it so:R23=2Ω +2Ω =4Ω and 1/Re=1/4Ω + 1/2Ω +1/2Ω = 5/4Ω Re=4Ω /5? Is this the right way of slowing it?
 
Dr.Phy said:
Then I did it so:R23=2Ω +2Ω =4Ω and 1/Re=1/4Ω + 1/2Ω +1/2Ω = 5/4Ω Re=4Ω /5? Is this the right way of solwing it?

No. What does parallel connection mean? Explain which resistors are connected in series and which are parallel.


ehild
 
R2,R3 are connected in series.And R4 R1 in paralel?
 
Dr.Phy said:
R2,R3 are connected in series.

Yes.

Dr.Phy said:
And R4 R1 in paralel?

No. The equivalent resistance of R2 and R3 is in parallel with R4. Do you see why?
 
Pranav-Arora said:
Yes.



No. The equivalent resistance of R2 and R3 is in parallel with R4. Do you see why?

Yes but i don't know how is it connected the R1,and how to find the eq reasistance of this circuit can u help me :/ .
 
  • #10
Dr.Phy said:
Yes but i don't know how is it connected the R1,and how to find the eq reasistance of this circuit can u help me :/ .

Draw figures after each reduction. R2 and R3 are in series as you said. Replace them with a single resistor and draw the figure.
 

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