What is the error in finding the volume of a cap of a sphere using integration?

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SUMMARY

The discussion focuses on calculating the volume of a spherical cap using integration techniques. The user attempted to derive the volume by rotating a circle around the y-axis and integrating, resulting in the equation π∫(h to r)(r² - y²)dy = π((1/3)h³ + (2/3)r³ - hr²). However, the computer program flagged this solution as incorrect, prompting a reevaluation of the limits of integration. The key takeaway is that as the height h approaches zero, the volume must also approach zero, indicating a potential error in the integration setup.

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Homework Statement


Find the volume of a cap of a sphere with radius r and height h.
A picture of it is given here;
http://sjc.ilrn.com/ilrn/bca/user/appletImage?dbid=1276286560



Homework Equations


The area of a circle is [tex]\pi\[/tex]r^2



The Attempt at a Solution


So I flattened the sphere into a circle and solved me equation for x;
x=sqrt(r^2-y^2)
Then I rotated it around the y-axis and integrated to find;
[tex]\pi[/tex][tex]\int[/tex][tex]\stackrel{h}{r}[/tex](r²-y²)dy= [tex]\pi[/tex]((1/3)h³+(2/3)r³-hr²)

But the computer program I do my homework on tells me that it wrong. Now I'm confused. What did I do wrong?
 
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As h->0 the volume should go to zero, right? Does yours? That's a clue something is wrong. Look at your limits of integration again. Are they right?
 

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