What is the expected time between bites in a jungle full of bees?

AI Thread Summary
In a jungle scenario, a bee lands on an individual every second with a probability of 0.5, and if it lands, it bites with a probability of 0.2. The expected time between bites can be calculated using the combined probabilities of landing and biting. The discussion touches on using Bayes' theorem to find the probability of being bitten in a single second and mentions the binomial distribution for modeling the number of bites over time. Participants explore the relationship between the number of seconds and bites to determine the expected value. Understanding these probabilities is key to solving the expected time between successive bites.
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You are in a jungle, at each second a bee lands on your arm with a probability of 0.5. Given that a bee lands on you, it will bite your arm with a probability of 0.2 and not do anything with a probability of 0.8, independently of all other mosquitoes. What is the expected time between successive bites?
 
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1) What is the probability that you will get bitten in a single second.

2) What distribution deals with the number of trials before a success?

3) Show some working if you want help
 
1) What is the probability that you will get bitten in a single second.

The probability of getting bitten (event B), given the bee lands on you (event A),
is given as P(B|A)=0.2
and P(A) is given as =0.5
is it correct to say P(A|B) = P (A and B) / P(A) and solve for P(B) ,
I am not sure how to solve for P(B) though, Bayes rule? 2) What distribution deals with the number of trials before a success?
Is this asking whether it is a binomial random variable
where k is the # of bites, n is the number of seconds (as each second is a new trial)
and Px(k) = (n C k) p^k * (1-p)^(n-k)

should the correct random variable equation should be
=(nCk) * P(B)^k (1-P(B))^(n-k)

I am not sure if it makes sense to make the number of bites equal to the number of seconds to find the E[X] time between successive bites.
(both equal to 2?)
 
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You are on the correct path with the conditional prob. What you are looking for is q = P(A and B), which is the binomial probability of being bitten.
 
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