What is the final velocity of a block on a ramp with given parameters?

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SUMMARY

The final velocity of a block sliding down a ramp can be calculated using the parameters provided: a height of 8m, a mass of 4.5kg, a coefficient of friction of 0.19, and an incline angle of 29 degrees. The acceleration due to gravity is 9.8m/s². The correct approach involves calculating the length of the incline and using the kinematic equation v² = u² + 2as, where the initial velocity (u) is 0. The acceleration (a) must account for both gravitational and frictional forces to determine the accurate final velocity.

PREREQUISITES
  • Understanding of kinematic equations, specifically v² = u² + 2as
  • Knowledge of gravitational acceleration (9.8m/s²)
  • Familiarity with the concepts of friction and incline angles
  • Ability to calculate the length of an incline from height and angle
NEXT STEPS
  • Calculate the length of the incline using trigonometric functions
  • Learn about the effects of friction on inclined planes
  • Explore advanced kinematic equations for varying acceleration
  • Study energy conservation principles in the context of inclined motion
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Students studying physics, particularly those focusing on mechanics and inclined motion, as well as educators seeking to clarify concepts related to acceleration and friction on ramps.

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Homework Statement


A block starts from rest at a heigh of 8m on a fixed inclined plane. The acceleration of gravity is 9.8m/s^2. What is the speed of the block at the bottom of the ramp? Answer in units of m/s.

Block mass = 4.5kg
coefficient of friction = 0.19
Angle of incline = 29 degrees
Distance from block to end of ramp = 8m


Homework Equations





The Attempt at a Solution



using a = (sin(theta)-ucos(theta)g I got 3.122 for a. However I'm not sure how to get a final velocity for the block from just the acceleration and distance.
 
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There's a kinematics equation that will directly give you the final velocity v2.

You know v1, a and d... you need v2... which equation will let you get it?
 
that would be sqrt of 2ax since vi is 0, but that answer comes out to 7.068 which is wrong so i must have my acceleration wrong
 
galuda said:
that would be sqrt of 2ax since vi is 0, but that answer comes out to 7.068 which is wrong so i must have my acceleration wrong

your acceleration looks right to me.

Did you use the right distance?

They give the height as 8m. But what is the length of the incline?
 
oh man I'm such an idiot. That would be the problem.
 

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