What is the force of the track on the block at A?

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Homework Help Overview

The problem involves a block of mass sliding down a frictionless track, released from a height, and the inquiry focuses on determining the force exerted by the track on the block at a specific point. The subject area includes dynamics and forces, particularly centripetal force and normal force considerations.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the nature of the track and its curvature, questioning whether it resembles a half-pipe. There is mention of the need to consider centripetal force and the effects of velocity and acceleration at the point of interest. Some participants also inquire about the vertical acceleration at point A and the forces acting on the block at that point.

Discussion Status

The discussion is ongoing, with participants exploring various interpretations of the problem. Guidance has been offered regarding the application of Newton's second law and the need to analyze forces at point A, though no consensus has been reached on the specifics of the solution.

Contextual Notes

There is a lack of visual reference for the track's shape, which may affect the clarity of the discussion. Participants are working with the assumption that the track is frictionless and are considering the implications of the block's motion and forces at the bottom of the track.

toastie
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Homework Statement


A block of mass m=1.3 kg slides down a frictionless track, as in the attachment diagram. The block is released at height h=4m. The radius of the curvature of the track at the bottom is R=1m. What is the force of the track on the block at A?

Untitled.jpg


Homework Equations


Fg+N=0


The Attempt at a Solution


I assumed that the track would be applying the normal force on the block, but the block does have some velocity and acceleration once it hits the bottom of the track, but I am not sure how to incorporate those.
 
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Is the track a half pipe like track? Either way you have to take the centripetal force into account.
 
The track goes down and then stops at B.
 
That may be, but you're asking what happens in a point A, since I cannot see the picture I don't know exactly how the track looks like. It is doubtful that it matters though I will say it again, centripetal force!
 
toastie said:
A block of mass m=1.3 kg slides down a frictionless track, as in the attachment diagram. The block is released at height h=4m. The radius of the curvature of the track at the bottom is R=1m. What is the force of the track on the block at A?

Hi toastie! :smile:

You need to use good ol' Newton's second law in the vertical direction … F = ma …

so what is the vertical acceleration (at point A)?

and how many forces are there at A? :wink:
 

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