What is the formula for the hydrate?

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To determine the formula for the hydrate of BaCl2, the initial mass of the hydrate was 61 grams, and after heating, the mass was reduced to 52 grams, indicating a loss of 9 grams of water. The molar mass of water is 18 grams, leading to the calculation of 0.5 moles of water lost. The moles of BaCl2 can be calculated based on its molar mass of 208.3 grams. Balancing the moles of BaCl2 and water reveals that the correct formula for the hydrate is BaCl2 * 2H2O. This aligns with the answer choices provided, confirming the hydrate's composition.
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Chemistry help please!

I've tried to work out the problem below, but I got weird answer, it's not even in one of the choices. Please help me solve this problem and show me out u got it. Thank you.
A sample of a hydrate of BaCl2 with a mass of 61 grams was heated until all the water was removed. The sample was then weighed and found to have a mass of 52 grams. What is the formula for the hydrate?
(A) BaCl2 * 5H2O
(B) BaCl2 * 4H2O
(C) BaCl2 * 3H2O
(D) BaCl2 * 2H2O
(E) BaCl2 * H2O
 
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Ba=137.3gtams Cl2=71 grams
BaCl2=208.3 grams --> but the answer in book says BaCl2 =244 grams.
61 grams - 52 grams = 9 grams
9grams / 18grams (H2O) = 1/2
so my answer is BaCl2 * 1/2 H2O, which doesn't make any sense @ all, and it's not one of the answer choices.
 
ok so you have 1/2 moles of H20, how many moles of BaCl2 do you have? balance them out and you'll get the answer.
 

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