What is the formula for the weight of a fluid block?

Thread starter werson tan
Start date Feb 25, 2016
Tags

Block Fluid Weight

AI Thread Summary

The formula for the weight of a fluid block is derived from the area of a square minus the area of a quarter circle, represented as ρg[(R^2) - π(R^2)]. The "1m" refers to the weight calculation being for a 1-meter length of the shaded area in the diagram. The discussion raises a question about whether the formula should instead be expressed as ρg(π)(R^2)h. The confusion stems from the interpretation of the areas involved in the calculation. Understanding the geometric shapes is crucial for correctly applying the weight formula.

Feb 25, 2016

werson tan

Homework Statement

why the formula of weight of fluid block is given by the formula of ρg[ (R^2) - pi(R^2) ] 1?

what does the 1m mean here ?
shouldn't it = ρg (pi) (R^2) h ?
2. Homework Equations

The Attempt at a Solution

Physics news on Phys.org

Feb 25, 2016

BvU

Science Advisor

Homework Helper

It's a square minus a quarter circle. ##W## is the weight of 1 m length (i.e. into the paper) of the area shaded grey in the right picture in Fig 3-36.

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...

View full post »

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...

View full post »

Thread 'Explain this asphalt sheen'

This problem is two parts. The first is to determine what effects are being provided by each of the elements - 1) the window panes; 2) the asphalt surface. My answer to that is The second part of the problem is exactly why you get this affect. And one more spoiler:

View full post »