What is the formula for velocity in SHM using differentiation?

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SUMMARY

The formula for velocity in Simple Harmonic Motion (SHM) is derived using differentiation from the displacement equation x = Asin(wt). The velocity, V, is calculated as V = dx/dt, which requires applying the chain rule to differentiate the sine function. The correct differentiation yields V = Awcos(wt), where A represents amplitude and w is the angular frequency. This formula is essential for understanding the dynamics of SHM.

PREREQUISITES
  • Understanding of Simple Harmonic Motion (SHM)
  • Familiarity with differentiation and derivatives
  • Knowledge of the chain rule in calculus
  • Basic concepts of trigonometric functions
NEXT STEPS
  • Study the application of the chain rule in calculus
  • Explore the characteristics and equations of Simple Harmonic Motion
  • Learn about angular frequency and its significance in SHM
  • Investigate the relationship between displacement, velocity, and acceleration in SHM
USEFUL FOR

Students of physics, mathematics enthusiasts, and anyone seeking to understand the principles of Simple Harmonic Motion and its mathematical foundations.

happyjoe
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Hey there, this should be a very simple problem, but again, I haven't had much guidance in finding formulas with differentiation. If anyone could help me with this i'd greatly appreciate it as it can help me to understand the others.

Characteristics of SHM are displacement (x) and time (t)

x = Asin(wt)

Velocity, V = dx/dt

Find a formula for velocity in SHM.

Im really confused as to what they're looking for.

Could it be that I simply need to do this?

ACos(w[tex]\frac{d}{dx}[/tex]t)?
 
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happyjoe said:
Hey there, this should be a very simple problem, but again, I haven't had much guidance in finding formulas with differentiation. If anyone could help me with this i'd greatly appreciate it as it can help me to understand the others.

Characteristics of SHM are displacement (x) and time (t)

x = Asin(wt)

Velocity, V = dx/dt

Find a formula for velocity in SHM.

Im really confused as to what they're looking for.

Could it be that I simply need to do this?

ACos(w[tex]\frac{d}{dx}[/tex]t)?

First a "differential" or "derivative" is NOT a "differential equation". I am moving this to "Calculus".

I don't see how you got the "x" inside the cos like that!

V= dx/dt= d(sin(wt))/dt. Now use the chain rule.
 
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