What is the gradient in polar coordinates?

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Discussion Overview

The discussion revolves around the representation of the gradient operator in polar coordinates, particularly in the context of the Laplacian operator. Participants explore the definitions and implications of first-order differential operators in vector analysis, as well as the appropriate expressions for these operators in curvilinear coordinates.

Discussion Character

  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant questions how to represent the first-order Laplacian operator in polar coordinates, referencing a Wikipedia page and a Math Stack Exchange post for context.
  • Another participant clarifies that the Laplacian is a second-order differential operator and asserts that there is no such thing as a first-order Laplacian, emphasizing the distinction between gradient, divergence, and curl as first-order operators.
  • Concerns are raised about the application of the gradient operator in curvilinear coordinates, noting that the expression for the gradient should not be treated as a vector in the same way as in Cartesian coordinates.
  • A participant reiterates the proposed expression for the gradient in polar coordinates, providing a formatting note for LaTeX support in the forum.

Areas of Agreement / Disagreement

Participants express differing views on the concept of a first-order Laplacian, with some asserting its non-existence while others focus on the representation of the gradient in polar coordinates. The discussion remains unresolved regarding the proper terminology and expressions to use.

Contextual Notes

There is a lack of consensus on the terminology used for first-order differential operators and the implications of applying Cartesian coordinate expressions to curvilinear coordinates. Participants reference external sources for definitions and expressions, but no definitive agreement is reached.

SeM
Hi, on this page: https://en.wikipedia.org/wiki/Laplace_operator#Two_dimensions

the Laplacian is given for polar coordinates, however this is only for the second order derivative, also described as \delta f . Can someone point me to how to represent the first-order Laplacian operator in polar coordinates? I found this at https://math.stackexchange.com/questions/586848/how-to-obtain-the-gradient-in-polar-coordinates, however, I am not sure its correct:

\nabla = \boldsymbol{e_r} \frac{\partial}{\partial r}+ \boldsymbol{e_{\theta}} \frac 1r \frac{\partial}{\partial \theta}.

Thanks!
 
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SeM said:
the first-order Laplacian operator
The Laplacian by definition is a second order differential operator. It is defined as the divergence of the gradient of a scalar field. There is no such thing as a first order Laplacian.

There are three first order differential operators you will encounter in basic vector analysis, the gradient, the divergence and the curl. You will often see them written as ##\nabla##, ##\nabla \cdot##, and ##\nabla \times##. However, you should be very careful here. The reason for expressing them like this is that it becomes correct to schematically write ##\nabla = \vec e_1 \partial_1 + \vec e_2 \partial_2 + \vec e_3 \partial_3## and apply the ##\cdot## and ##\times## as scalar and cross products with the derivatives acting on what is to the right. This only works in Cartesian coordinates. In curvilinear coordinates you will have to find the appropriate expressions and they will not involve writing ##\nabla## as a vector and blindly applying the scalar and cross products.

See https://en.wikipedia.org/wiki/Curvilinear_coordinates#Differentiation for the correct expressions in general coordinates. This is also something you should be able to find in any introductory textbook on vector analysis.

Please also be aware that the "A" tag you put on this thread would imply that you have a graduate level understanding of the subject and expect an answer at that level. Based on the content of the question, the thread level is at most an "I" and I have changed it accordingly.
 
SeM said:
\nabla = \boldsymbol{e_r} \frac{\partial}{\partial r}+ \boldsymbol{e_{\theta}} \frac 1r \frac{\partial}{\partial \theta}.
By the way, this forum supports ##\LaTeX## but you need to put double-$ signs before and after the code:$$
\nabla = \boldsymbol{e_r} \frac{\partial}{\partial r}+ \boldsymbol{e_{\theta}} \frac 1r \frac{\partial}{\partial \theta}.
$$
 
Thanks!
 

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