What is the Gravitational Acceleration at a Height Equal to Earth's Diameter?

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    Gravitation
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Homework Help Overview

The discussion revolves around determining the gravitational acceleration at a height equal to the Earth's diameter from its surface, starting from the known value of 9.81 m/s² at the surface. Participants explore the implications of gravitational force and its relationship with distance from the Earth's center.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the formula for gravitational force and its application to find gravitational acceleration at different heights. There are questions about the relationship between force and acceleration, and how to express gravitational acceleration in terms of known values.

Discussion Status

Several participants are engaged in exploring the mathematical relationships and ratios involved in gravitational acceleration. Some guidance has been provided on how to express gravitational acceleration at height in relation to its value at the surface, but there remains some confusion about the calculations and the use of mass in the equations.

Contextual Notes

Participants are working under the constraints of a homework problem, which includes specific values for Earth's radius and the requirement to express gravitational acceleration at a height equal to the Earth's diameter. There is also a mention of available multiple-choice answers that may influence the discussion.

  • #31
Deebu R said:
g*=0.11 x 9.81=1.079m/s^2.
Is that the answer?
What if I told you that 0.11111...= 1/9

What would your answer be then?
 
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  • #32
PeroK said:
It can only be one of those!
Well yeah. I guess...what will I do if the options are like that?Should I go for option d?
 
  • #33
Chestermiller said:
What if I told you that 0.11111...= 1/9

What would your answer be then?
Actually I got the answer as 1/9 but since the option given are in decimal form I divided it to get 0.1111...
 
  • #34
Deebu R said:
Actually I got the answer as 1/9 but since the option given are in decimal form I divided it to get 0.1111...
Well, 9.81/9 = 1.09
 
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  • #35
Chestermiller said:
Well, 9.81/9 = 1.09
OHHHHHHH! I did not think of that. This is mind blowing. I am happy. Thank you very much for your time and effort. It felt really really nice.
 
  • #36
In the end there was no complicated calculation. It was way more simple than I thought. I felt like I just watched a suspense thriller. Thank you guys very much for helping me.
 
  • #37
Deebu R said:
In the end there was no complicated calculation. It was way more simple than I thought. I felt like I just watched a suspense thriller. Thank you guys very much for helping me.

You got there in the end, but effectively all you had to do was:

Gravitational acceleration -> inverse square law -> 3x distance -> (1/3) squared = 1/9 x acceleration -> 9.81/9 = 1.09
 
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  • #38
Deebu R said:
In the end there was no complicated calculation. It was way more simple than I thought. I felt like I just watched a suspense thriller. Thank you guys very much for helping me.
You should really be thanking Perok and BvU, not me.
 
  • #39
If you promise to work with symbols as much as you can I'm more than rewarded...
 

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