What is the Impulse Delivered by an Elevator to a Moving Package?

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The discussion centers on calculating the impulse delivered to a 1200N package by an elevator moving at a constant speed. It is established that since the elevator's acceleration is zero, the net force acting on the package is also zero, leading to the conclusion that the overall impulse is zero. However, the specific impulse delivered by the elevator floor is debated, with the consensus leaning towards 3600 Ns upward. The distinction is made that impulse is a vector quantity, and the forces acting on the package include the upward reaction force from the elevator floor and the downward weight of the package. Ultimately, the correct answer to the impulse delivered by the elevator floor is identified as 3600 Ns up.
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Homework Statement


Moving at a constant speed, an elevator lifts a 1200N package 10m in 3 sec. During this time, the impulse delivered to the package by the elevator floor is
a) zero
b) 12000 Nm up
c) 3600 Ns up
d) 12000 Ns up


Homework Equations


change in momentum = net Force*time interval


The Attempt at a Solution


zero b/c if it's moving at constant speed, the acceleration is zero. therefore, net force = zero.
 
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There are two forces acting on the body -- reaction force of the elevator floor acting upward, and the weight of the body acting downward. The net force and the net impulse is zero, but the question specifically asks for the impulse delivered to the package by the floor, and thus should be 3600 Ns up. (Note that impulse is a vector quantity.)
 
Thanks ShootingStar. You've been a great help. :smile:
 
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