What is the Infimum of the Set of Rational Numbers with respect to pi?

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SUMMARY

The infimum of the set of rational numbers with respect to π is definitively 0. This conclusion is based on the fact that there exist rational numbers arbitrarily close to any real number, including π. Therefore, the greatest lower bound of the absolute difference |x - π|, where x is a rational number, is established as 0. This is supported by the properties of rational numbers in relation to real numbers.

PREREQUISITES
  • Understanding of real numbers and rational numbers
  • Familiarity with the concept of infimum and greatest lower bound
  • Basic knowledge of absolute value functions
  • Experience with mathematical proofs and justifications
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  • Study the properties of real numbers and their density in the rational number set
  • Explore the concept of limits and convergence in real analysis
  • Learn about the completeness property of real numbers
  • Investigate the implications of the Archimedean property in number theory
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Students in mathematics, particularly those studying real analysis, number theory, or anyone interested in the properties of rational and real numbers.

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Homework Statement


Find inf{|x-pi|:x[tex]\in[/tex]Q}

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The Attempt at a Solution


I was thinking that the greatest lower bound must be 0, but that seemed a bit simple. Is there any justification I have to give for this?

Any help would be much appreciated. Cheers. :)
 
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Yes, there exist rational number arbitrarily close to any real number and, in particular, arbitrarily close to [itex]\pi[/itex]. The infimum of [itex]|x- \pi|[/itex] for x rational is 0.
 


Thanks for the clarification. :)
 

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