What is the initial charge of the second object in Coulombs?

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The problem involves two objects, where the first object has a charge of 1 C and gains approximately 9.38 x 10^18 electrons, resulting in a net charge of about -0.5008 C. When this charged object comes into contact with a second object, the second object ends up with a charge of 0.9 C. To find the initial charge of the second object, it is essential to assume both objects are conductors and identical, allowing for charge redistribution upon contact. The discussion emphasizes the need for these assumptions to accurately analyze the charge transfer process. Understanding the behavior of charges in conductors is crucial for solving the problem effectively.
JessicaHelena
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Homework Statement


Suppose an object has a charge of 1 C and gains #9.38 ✕ 10^18# electrons. When another object is brought in contact with the first object (after it gains the electrons), the resulting charge on the the second object is 0.9 C. What was the initial charge (in Coulombs)?

Homework Equations



1 electron has a charge of about #-1.6 \times 10^{-19}.

The Attempt at a Solution



Since the first object (call it object A) has a charge of 1C but gains #9.38 ✕ 10^18#, and using dimensional analysis #(9.38 ✕ 10^18 electrons) \times (-1.6 \times 10^{-19} C)/(1 electron) = -1.5008#, the net charge on object A is -0.5008 C. But I'm not sure how to go about solving for the initial charge on the second object?
 
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Even though the problem does not state so, the "objects" must be conductors for this to make sense. When the objects are brought in contact what do you think happens to the charges? Do they stay where they are or do they move?
 
kuruman said:
Even though the problem does not state so, the "objects" must be conductors for this to make sense.
And we need to assume the objects are identical, and brought into contact in a symmetric manner, no?
 
haruspex said:
And we need to assume the objects are identical, and brought into contact in a symmetric manner, no?
Yes.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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