What is the initial momentum of the sled-person system?

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Homework Help Overview

The problem involves calculating the initial momentum of a sled-person system, where a person of mass 75.0 kg runs and jumps onto a sled of mass 10.0 kg. The person is moving at 3.00 m/s, while the sled is moving at 2.00 m/s in the same direction. The discussion includes questions about the initial and final momentum of the system and the resulting velocity after the person jumps onto the sled.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the calculation of momentum, with some questioning whether to treat the sled and person as a single unit or to calculate their momenta separately. There is also a focus on the conservation of momentum and the implications of rounding in numerical answers.

Discussion Status

The discussion is ongoing, with participants providing feedback on each other's calculations and questioning the accuracy of rounding. Some guidance has been offered regarding the treatment of the system as separate entities versus a combined unit, but no consensus has been reached on the correctness of the answers provided.

Contextual Notes

Participants are navigating potential errors in numerical calculations and rounding conventions, with some expressing uncertainty about their answers and seeking validation from others.

Glenboro
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1. Homework Statement
A 75.0 kg person runs at 3.00 m/s and jumps onto a sled of mass 10.0 kg already moving in the same direction as the person at 2.00 m/s.

a) What is the initial momentum of the sled-person system?
b) What will the final momentum of the sled and the person be?
c) What is the velocity of the sled and the person after the person jumps on the sled?2. Homework Equations
P = mv
Pi = Pf (when momentum is conserved)
m1vi + m2vi = m1vf + m2vf3. The Attempt at a Solution
a)P = mv
p = (75.0kg)(3.00m/s) + (10.0kg)(2.00m/s)
p = +245 kg(m/s)

The questions a) is little tricky, I am not sure if I should get momentum of being one unit (e.g 75.0 kg + 10.0kg)(3.00m/s+2.00m/s) or what I did originally

b) Pi = Pf (when momentum is conserved)
Therefore pf = 245 kg(m/s)

C) m1vi + m2vi = m1vf + m2vf
245 kg(m/s) = (75kg +10kg)(v2f)
V2f = 2.89 m/s
 
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a small error on c
 
Glenboro said:
not sure if I should get momentum of being one unit (e.g 75.0 kg + 10.0kg)(3.00m/s+2.00m/s)
No, that would be quite wrong. Nothing here is moving at 5m/s.
skarner said:
a small error on c
How small? I get 2.882...
 
haruspex said:
No, that would be quite wrong. Nothing here is moving at 5m/s.

How small? I get 2.882...
Thank you, I was going to do as one unit, but I thought something was wrong, so I did the separately.
Do you think all my answers are correct though?
 
Glenboro said:
Thank you, I was going to do as one unit, but I thought something was wrong, so I did the separately.
Do you think all my answers are correct though?
Apart from the tiny numerical error in c, yes.
 
haruspex said:
Apart from the tiny numerical error in c, yes.
Hm.. I don't recognize any error, I just rounded to 2.89 m/s from 2.882 m/s which you just wrote.
 
Glenboro said:
Hm.. I don't recognize any error, I just rounded to 2.89 m/s from 2.882 m/s which you just wrote.
2.88 is nearer to 2.882 than 2.89 is. Unless you specifically need to round up, round to nearest.
 
haruspex said:
2.88 is nearer to 2.882 than 2.89 is. Unless you specifically need to round up, round to nearest.
LoL I must've been drunken sorry
 

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