What is the Initial Phase Angle and First Maximum Current in an AC Circuit?

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The initial phase angle for the AC circuit is calculated as 0.6 radians, which converts to approximately 34.38 degrees. To find the first maximum current, the equation 100πτ + 0.6 = π/2 is used, leading to an algebraic error in the attempt. The correct approach involves solving for τ, but the user miscalculated the steps. The discussion also notes that the thread is more suitable for the "Introductory Physics" forum rather than the "Calculus" forum. Clarifying the algebraic mistake is essential for accurate results.
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Homework Statement


i = 15 sin(100π.t + 0.6)
a) I need to state the initial phase angel in rads and degrees.
b) I also need to work out current at first maximum value.

Homework Equations


i=A*sin(ωτ+∅)

The Attempt at a Solution



a) ∅=100∏*0+0.6
∅= 0.6 rads. ∴0.6*180/∏=34.37746771°

b) first current max =∏/2 rad's
100∏τ+0.6=∏/2
100τ+0.6=1/2
200τ+1.2=1
t=1/(200+1.2)
t=4.970178926*10^-3
 
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You've made an algebraic mistake in your part b), but yes, you are on the right track. By the way, a thread like this belongs in the "Introductory Physics" forum, not the Calculus forum.
 
Steely Dan said:
You've made an algebraic mistake in your part b), but yes, you are on the right track. By the way, a thread like this belongs in the "Introductory Physics" forum, not the Calculus forum.

where abouts did i go wrong?
 
steveandy2002 said:
100∏τ+0.6=∏/2
100τ+0.6=1/2

:redface:
 
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