SUMMARY
The integral of 2^(2x) is calculated as 2^(2x) / (2Ln(2)). This result is derived by rewriting 2^(2x) in terms of the exponential function, specifically e^(2Ln(2)x). By substituting u = 2Ln(2)x, the integral simplifies to (1/(2Ln(2))) * ∫e^u du, leading to the final answer. The factor of 2Ln(2) arises from the differentiation of the substitution used in the integration process.
PREREQUISITES
- Understanding of integral calculus
- Familiarity with exponential functions
- Knowledge of substitution methods in integration
- Basic logarithmic properties
NEXT STEPS
- Study integration techniques involving exponential functions
- Learn about the properties of logarithms and their applications in calculus
- Explore advanced substitution methods in integral calculus
- Practice solving integrals of the form ∫a^(bx) dx
USEFUL FOR
Students preparing for calculus exams, educators teaching integral calculus, and anyone seeking to strengthen their understanding of integration techniques involving exponential functions.