What is the integral of 2^(2x)? tonight, exam is tomorrow

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SUMMARY

The integral of 2^(2x) is calculated as 2^(2x) / (2Ln(2)). This result is derived by rewriting 2^(2x) in terms of the exponential function, specifically e^(2Ln(2)x). By substituting u = 2Ln(2)x, the integral simplifies to (1/(2Ln(2))) * ∫e^u du, leading to the final answer. The factor of 2Ln(2) arises from the differentiation of the substitution used in the integration process.

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what is the integral of 2^(2x)? need help tonight, exam is tomorrow

teacher says the answer is: 2^(2x) / 2Ln(2)

why 2 times Ln(2)?
 
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Observe that:

$$2^{2x}=e^{\ln\left(2^{2x}\right)}=e^{2\ln\left(2\right)x}$$

Hence:

$$I=\int 2^{2x}\,dx=\int e^{2\ln\left(2\right)x}\,dx$$

Let:

$$u=2\ln\left(2\right)x\implies du=2\ln\left(2\right)\,dx$$

And so we have:

$$I=\frac{1}{2\ln\left(2\right)}\int e^u\,du$$

Can you proceed?
 

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