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can anybody help me with this problem
Evaluate :
integral 3x (sinx/cos^4x) dx
Evaluate :
integral 3x (sinx/cos^4x) dx
What is the Integral of 3x (sinx/cos^4x) dx?
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courtrigrad
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Is it [tex]\int \frac{3x\sin x}{\cos^{4} x}[/tex]?
Rewrite it as [tex]3\int x\tan x\ sec^{3} x[/tex] and use integration by parts
Rewrite it as [tex]3\int x\tan x\ sec^{3} x[/tex] and use integration by parts
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i know the equation for intergration by parts is
intergral u dv = uv -intergral v du
can u tell me which variable is which?...u, du, v, dv=?...there seems to have 3 different variable.
intergral u dv = uv -intergral v du
can u tell me which variable is which?...u, du, v, dv=?...there seems to have 3 different variable.
courtrigrad
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Let [tex]u = x[/tex] and [tex]dv = \ tan x \sec^{3} x[/tex]. You will then need to use integration by parts on [tex]dv[/tex] to get [tex]v[/tex].
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Science Advisor
Homework Helper
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I'm sure courtrigrad meant [itex]u= x[/itex] and [itex]dv= tan x sec^3 xdx[/itex] (with out the "x" in dv).
courtrigrad
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yep, thanks catching that 