What is the Integral of sin^3(x)cos^2(x)?

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Homework Statement



[tex]\int sin^3(x)cos^2(x)dx[/tex]

The Attempt at a Solution



[tex]\int sin^3x(1-sin^2x)dx =[/tex] [tex]\int sin^3x- sin^5xdx[/tex]

i get stuck here what do i do next and is this even right
 
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we could use complex numbers (de moivres theorem) here and express sin^5x, sin^3x in terms of sin5x, sin3x

(directly integratable)
 
Jumpy Lee said:

Homework Statement



[tex]\int sin^3(x)cos^2(x)dx[/tex]

The Attempt at a Solution



[tex]\int sin^3x(1-sin^2x)dx =[/tex] [tex]\int sin^3x- sin^5xdx[/tex]

i get stuck here what do i do next and is this even right

HINT

[tex]\int \left(1-\cos^{2}x\right) \cos^{2}x \left(\sin x \ dx\right)[/tex]

Do you know how to use the substitution method ?
 
u = cos x -du = sin x dx right?
 
Last edited:
-[tex]\int (u^2 - u^4)du =[/tex] -u^3/3 + u^5/5 +c = -cos^3x/3 + cos^5x/5 + c