What is the Kinematics Problem for a California Condor Carrying Carrion?

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A California Condor carrying carrion experiences a momentary upward velocity of 12.8 m/s before the carrion falls, hitting a cliff outcropping 32.1 m below. The problem involves determining the speed of the carrion upon impact using kinematic equations. Key considerations include the direction of velocity and acceleration due to gravity, which affects the signs in the equations. The upward motion of the bird before release means the initial velocity is positive, while gravity acts downward. Understanding these concepts leads to solving the problem correctly.
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A California Condor is approaching its nest with a large chunk of carrion in its beak. As it approaches, it makes an upward swoop, achieving a momentary upward velocity of 12.8 m/s when the carrion falls from its mouth, hitting a cliff outcropping 32.1 m below. Determine the speed of the carrion upon hitting the outcropping.

This is a problem from Physics Classroom that I have to solve for AP Physics summer homework. I've never done physics before, so I'm finding it hard to even do basic problems.

Help please?

I've tried setting v0=12.8, x=32.1, a=g=9.8 and plugging it into vf^2=v0^2+2ax.
 
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When the carrion is set loose, which way is it going? Up or down? How does gravity affect this?
 
The carrion goes down. I think that gravity makes it go down faster?
 
yjstudent said:
The carrion goes down.

No. Read the description. Just before the carrion is released the entire system bird + carrion is going UP.

I think that gravity makes it go down faster?

First it will need to slow it to a (momentary) halt.

What does this all mean with regard to the signs of v_0 and g?
 
Opposite signs? Since v0 goes up and g goes down
 
Exactly! Now you need to choose a positive direction - either up or down - and that should fix the signs for all the quantities (the distance, the velocity, and the acceleration), so you will be able to write down the equations.
 
Yay thanks I got the answer..
 
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