What is the Largest Quantum Number for Li3+ with a 60 Å Orbital Radius?

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The largest quantum number for the Li3+ ion with an orbital radius of 60 Å is discussed, noting that Li3+ is a bare nucleus with no electrons. The calculation presented suggests that the quantum number can be approximated using the formula √(60×3/0.529), yielding results around 18 or 20 to one significant figure. The discussion emphasizes the unique nature of Li3+ in this context. Overall, the focus is on determining the quantum number relevant to the specified orbital radius.
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TL;DR Summary: Quantum number of a state

What is the largest quantum number of a state of the Li3+ ion with an orbital radius equal to 60 A?

I tried solving the question as below
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Apart from belonging in the homework section, Li3+ is a bare nucleus. It has no electrons.
 
Apart from Li3+ being a bare nucleus, ##\sqrt{\dfrac{60\times 3}{0.529}}=18## or ##20## to one sig. fig.
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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