What is the Largest Quantum Number for Li3+ with a 60 Å Orbital Radius?

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The largest quantum number for the Li3+ ion with an orbital radius of 60 Å is discussed, noting that Li3+ is a bare nucleus with no electrons. The calculation presented suggests that the quantum number can be approximated using the formula √(60×3/0.529), yielding results around 18 or 20 to one significant figure. The discussion emphasizes the unique nature of Li3+ in this context. Overall, the focus is on determining the quantum number relevant to the specified orbital radius.
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TL;DR Summary: Quantum number of a state

What is the largest quantum number of a state of the Li3+ ion with an orbital radius equal to 60 A?

I tried solving the question as below
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Apart from belonging in the homework section, Li3+ is a bare nucleus. It has no electrons.
 
Apart from Li3+ being a bare nucleus, ##\sqrt{\dfrac{60\times 3}{0.529}}=18## or ##20## to one sig. fig.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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