What is the magnetic field inside a cylinder?

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The magnetic field inside a cylinder is uniform, despite the dependence of bound surface current density on the angle of magnetization. The axis of the cylinder is perpendicular to the magnetization vector, which plays a crucial role in determining the magnetic field. The symmetry of the cylinder ensures that the magnetic field does not vary with angle. Smyrhe's classic text provides an exact solution to this problem, confirming the uniformity of the magnetic field. Understanding these principles is essential for solving related magnetic field problems.
Jefferson Yun
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The axis of the cylinder is perpendicular(not parallel) to M, magnetization. It's not hard to find bound surface current density, but it depends on the angle while the answer says the magnetic field is uniform inside the cylinder.
Anyone can silve this problem??
 
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It can't depend on angle, due to symmetry. Smyrhe solves this problem exactly in his classic text.
 
Thread 'Motional EMF in Faraday disc, co-rotating magnet axial mean flux'

Thread 'Motional EMF in Faraday disc, co-rotating magnet axial mean flux'

So here is the motional EMF formula. Now I understand the standard Faraday paradox that an axis symmetric field source (like a speaker motor ring magnet) has a magnetic field that is frame invariant under rotation around axis of symmetry. The field is static whether you rotate the magnet or not. So far so good. What puzzles me is this , there is a term average magnetic flux or "azimuthal mean" , this term describes the average magnetic field through the area swept by the rotating Faraday...
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