What Is the Magnetic Force on a Single Electron?

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Homework Help Overview

The discussion revolves around calculating the magnetic force on a single electron, utilizing the equation F = BIl. Participants are exploring the implications of electron density and its relationship to the total number of electrons in a given volume.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants initially attempt to apply the magnetic force equation but question the interpretation of electron density versus the number of free electrons. There is a discussion on how to derive the total number of electrons from the density and volume of the wire.

Discussion Status

Some participants have provided insights into the correct interpretation of electron density and its calculation, suggesting a path forward in understanding how to find the total number of electrons. However, there is no explicit consensus on the final answer.

Contextual Notes

Participants are navigating the distinction between electron density and the actual number of free electrons, which is critical to solving the problem accurately. The calculations involve assumptions about the volume of the wire and the density provided.

jsmith613
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Homework Statement


question - see image
attachment.php?attachmentid=45908&d=1333628221.png

Homework Equations


The Attempt at a Solution



so I use the equation F = BIl
F = 0.2 * 0.4 * 8 = 0.64
Surely I just divide it by the number of electrons (8*1028) to get the answer
BUT this does not give the correct answer.

The correct answer is D?
 

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jsmith613 said:
so I use the equation F = BIl
F = 0.2 * 0.4 * 8 = 0.64
Surely I just divide it by the number of electrons (8*1028) to get the answer
BUT this does not give the correct answer.

The correct answer is D?

Ah. That's not the number of free electrons, that's the density of free electrons.
 
gneill said:
Ah. That's not the number of free electrons, that's the density of free electrons.
so density / area = number/m
right?
 
Last edited:
jsmith613 said:
so density / area = number/m
right?

##\rho = \frac{n}{volume}##

If you calculate the volume of the wire you can find the total n.
 
gneill said:
##\rho = \frac{n}{volume}##

If you calculate the volume of the wire you can find the total n.

so n = density * volume
n = 8 * 1028 * 0.4 * 10-6

therefore answer = D

thanks
 

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