What is the Magnitude of Attractive Force Between a Satellite and Earth?

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To calculate the attractive force between a satellite and Earth, the formula F=GM(sat)M(Earth)/R^2 is used, where the mass of Earth is 6.0 x 10^24 kg, not 6.0 x 10^7 kg. The satellite's mass is 1500 kg, with an orbital period of 86400 seconds and a radius of 42200000 meters. It's crucial to include the Earth's radius when determining the distance for the calculation. The correct distance should be the orbital height above Earth plus Earth's radius. The initial calculation of 3.37 x 10^32 was incorrect due to these factors.
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A 1500 kg satellite is orbiting planet earth. The period is 86400 seconds and the radius is 42200000 meters. To determine the magnitude of attractive force... you use equation F=GM(sat)M(Earth)/R2. I know that the mass of Earth is 6.0*10(exp)7 kg and the gravitational constant is 6.67*10(exp negative 11) N*m2/kg2. My answer comes out to be 3.37 *10(exp)32, which is not one of my options?
 
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did you account for the radius of the Earth in your calculation. The distance you need to use is orbital height above erath + Earth's radius.

Regards,

Nenad
 
The mass of the Earth is not 6*10^{7}kg. It is 6*10^{24} kg.

and don't use r2, but rather r^2, but I think you knew that already or you probably would have put 2r instead
 
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