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What is the magnitude of the electric field?

  1. Jul 9, 2014 #1
    1. The problem statement, all variables and given/known data
    Two charged particles are fixed on the x-axis 11 cm apart. The one on the left has a net charge of +25uc and the one on the right has a net charge of -11uc. What is the magnitude of the electric field 10 cm to the right of the negative charge?


    2. Relevant equations
    E = (kq)/r^2


    3. The attempt at a solution
    When I plug in 9.0 x 10^9 for k, 11.0 x 10^-6 C for q and 0.1 m for r, I get the wrong answer.

    Thanks for any help!
     
    Last edited: Jul 9, 2014
  2. jcsd
  3. Jul 9, 2014 #2

    TSny

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    Homework Helper
    Gold Member

    Hello, zoomba91210.

    Both charges contribute to the electric field at the point located 10 cm to the right of the negative charge. ("Superposition principle")
     
    Last edited: Jul 9, 2014
  4. Jul 11, 2014 #3
    Suppose that a +ve unit test charge is located at a point on which E is to be calculated. Find the net force on that charge due to the two charges.
     
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