What is the magnitude of the force of the block on the horizontal surface?

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SUMMARY

The magnitude of the force exerted by a block on a horizontal surface is determined by its weight and any opposing forces acting on it. In this case, a block weighing 2.9 N is subjected to an upward force of 1.3 N from a vertical string. The net force acting on the surface is calculated as 2.9 N - 1.3 N, resulting in a force of 1.6 N exerted by the block on the horizontal surface.

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Nance
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Homework Statement



A block with a weight of 2.9 N is at rest on a horizontal surface. A 1.3 N upward force is applied to the block by means of attached vertical string.
(a) What is the magnitude of the force of the block on the horizontal surface?

Homework Equations



I'm not sure really..

The Attempt at a Solution



I have tried solving this from several different angles. I thought to use F=2.9Nx9.81-1.3, but I believe that is incorrect.
 
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Nance said:
I have tried solving this from several different angles. I thought to use F=2.9Nx9.81-1.3, but I believe that is incorrect.

This looks right except I don't think you want to multiply the 2.9N force with a 9.81, which I believe would be the acceleration of the block towards the Earth in [tex]ms^{-2}[/tex]. Force cross acceleration is not something people are usually interested in, especially if they are in the same direction, because it equals zero.

Imagine the block pushing the surface with 2.9N force and an opposing force of 1.3N acts in the opposite direction to cancel out 1.3N of the original force acting on the surface. Hope this helped.
 
Thank you!
 

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