What Is the Mass Percentage of Each Component in a SrCO3 and BaCO3 Mixture?

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To determine the mass percentage of each component in the SrCO3 and BaCO3 mixture, the total mass of the mixture is 1.60g, and the reaction with hydrochloric acid produces 0.421g of carbon dioxide. The molar masses of SrCO3 and BaCO3 are needed to relate the amount of CO2 produced to the original components. By calculating the moles of CO2 and using stoichiometry, the individual masses of SrCO3 and BaCO3 can be found. This will allow for the calculation of the mass percentages of each component in the mixture.
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A certain mixture contains only SrCO3 and BaCO3. When 1.60g of this mixture is treated with hydrochloric acid, 0.421g of carbon dioxide gas is liberated. Calculate the mass percentage of each component in the mixture. Reaction of the carbonate with the acid:

MCO3(s)+2H(aq)+--->M+2(aq) + H2O(l) +CO2(g).

Im completely lost on this problem, its kinda the same as the last I guess.

Any help will be appreciated.
 
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