What is the Maximum Acceleration for Two Connected Masses on a Pulley System?

  • Thread starter Thread starter Kaze105
  • Start date Start date
  • Tags Tags
    Acceleration Mass
Click For Summary
SUMMARY

The maximum acceleration for two connected masses on a pulley system occurs when the mass m1 is set to zero. Given the values m1 = 5kg and m2 = 1kg, the acceleration can be calculated using the formula (m2)/(m1 + m2) * g, where g represents gravitational acceleration. When m1 is zero, the equation simplifies to a = g, indicating that the maximum acceleration is equal to the acceleration due to gravity, approximately 9.81 m/s².

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Basic knowledge of pulley systems
  • Familiarity with gravitational acceleration (g = 9.81 m/s²)
  • Ability to manipulate algebraic equations
NEXT STEPS
  • Study the effects of friction on pulley systems
  • Learn about tension in strings and its role in dynamics
  • Explore advanced topics in classical mechanics, such as energy conservation
  • Investigate real-world applications of pulley systems in engineering
USEFUL FOR

Students studying physics, educators teaching mechanics, and anyone interested in understanding dynamics in pulley systems.

Kaze105
Messages
8
Reaction score
0

Homework Statement


Consider two masses m1 and m2 connected by a thin string.

Assume the following values m1 = 5kg, m2 = 1 kg. Ignore friction and mass of the string.

The two blocks are connected by a thin string, which m2, hangs down freely, while the other is on a flat surface. There is a pulley at the edge of the surface so that m2 hangs down.

What should the balue of mass m1 be to get the largest possible value of accelaratio nof the two masses. What would be that maximum acceleration.

Homework Equations



(m2)/(m1 + m2) * g = a


The Attempt at a Solution



I know that the lower m1 is, the higher the acceleration would be. But what would the maximum be?
 
Physics news on Phys.org
The mass of m1 can be greater than or equal to zero. The maximum occurs when m1 is equal to zero. The equation you give reduces to a=g. Therefore the maximum acceleration is equal to g.
 
Ah i see, thank you very much
 

Similar threads

Replies
23
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 17 ·
Replies
17
Views
3K
Replies
4
Views
1K
Replies
25
Views
4K
  • · Replies 33 ·
2
Replies
33
Views
3K
Replies
16
Views
2K
Replies
16
Views
2K
Replies
2
Views
2K